Servlet获取ajax传递的json值

2017-2-7 13:40| 发布者: zhangjf| 查看: 496| 评论: 0

摘要: Servlet获取ajax传递的json值其实标题可直接写为“记一件愚蠢的事”。另外声明这是只是一篇水文。原本都用SpringMVC和ajax进行前后台的交互，今天打算试试用原始的Servlet与其进行交互。起初是打算实现一个跳转（ ...

其实标题可直接写为“记一件愚蠢的事”。另外声明这是只是一篇水文。

原本都用SpringMVC和ajax进行前后台的交互，今天打算试试用原始的Servlet与其进行交互。

起初是打算实现一个跳转（虽然感觉没什么意义）：

Action如下：

package per.zww.ajax.action;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/ServletAjax")
public class ServletAjax extends HttpServlet {
private static final long serialVersionUID = 1L;
public ServletAjax() {
super();
}
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
this.doPost(request, response);
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
request.getRequestDispatcher("hello.jsp").forward(request, response);
}
}

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JSP页面如下：

<%@ page language="java" contentType="text/html; charset=utf-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Insert title here</title>
<script src="<%= request.getContextPath() %>/js/jquery-1.7.2.min.js"></script>
<script type="text/javascript">
$(function(){
$("#test").click(function(){
$.post("ServletAjax");
});
})
</script>
</head>
<body>
<input type="button" name="test" id="test" value="测试"/>
</body>
</html>

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run运行

坑爹了，它怎么不跳转呢？！用firebug查看，没错啊200OK。怎么不跳转？！

坑爹了，好久没碰连ajax使用都忘了。url是发送请求的地址，若是想要想跳转需在function回调函数里面写上window.location.href="ServletAjax";

下面开始正题

其实Servlet获取ajax传递的json值很容易，只需在servlet用request.getParameter()方法即可。

Action如下：

package per.zww.ajax.action;
import java.io.IOException;
import javax.servlet.ServletException;
import javax.servlet.annotation.WebServlet;
import javax.servlet.http.HttpServlet;
import javax.servlet.http.HttpServletRequest;
import javax.servlet.http.HttpServletResponse;
@WebServlet("/ServletAjax")
public class ServletAjax extends HttpServlet {
private static final long serialVersionUID = 1L;
public ServletAjax() {
super();
}
protected void doGet(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
// TODO Auto-generated method stub
this.doPost(request, response);
}
protected void doPost(HttpServletRequest request, HttpServletResponse response) throws ServletException, IOException {
String username=request.getParameter("username");
System.out.println(username);
request.getRequestDispatcher("hello.jsp").forward(request, response);
}
}

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JSP页面如下：

<%@ page language="java" contentType="text/html; charset=utf-8"%>
<!DOCTYPE html PUBLIC "-//W3C//DTD HTML 4.01 Transitional//EN" "http://www.w3.org/TR/html4/loose.dtd">
<html>
<head>
<title>Insert title here</title>
<script src="<%= request.getContextPath() %>/js/jquery-1.7.2.min.js"></script>
<script type="text/javascript">
$(function(){
$("#test").click(function(){
$.post("ServletAjax",{username:"zhaoww"},function(data){
window.location.href="ServletAjax";
});
});
})
</script>
</head>
<body>
<input type="button" name="test" id="test" value="测试"/>
</body>
</html>

复制代码

来自： http://www.cnblogs.com/zhaoww/p/5115134.html

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